C# การใช้งาน DataTable กับ DataGridView (MS Access 2007) แบบบ้านๆ

public static  class Database
    {
      public static string PostCodeConnectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=X:\\DATA\\PostCode.mdb;Persist Security Info=True;Jet OLEDB:Database Password=4410210091";
      public static string CONTACTConnectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=X:\\DATA\\CONTACT.mdb;Persist Security Info=True;Jet OLEDB:Database Password=4410210091";
      public static System.Data.DataTable GetTableForm(string _SQL, string strConn)
      {

          System.Data.DataSet ds = new System.Data.DataSet();
          System.Data.OleDb.OleDbConnection conn = new System.Data.OleDb.OleDbConnection(strConn);
          conn.Open();
          System.Data.OleDb.OleDbDataAdapter adapter2 = new System.Data.OleDb.OleDbDataAdapter(_SQL, conn);
          adapter2.Fill(ds);
          return ds.Tables[0];

      }
    }

public static  class Database
    {
      public static string PostCodeConnectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=X:\\DATA\\PostCode.mdb;Persist Security Info=True;Jet OLEDB:Database Password=4410210091";
      public static string CONTACTConnectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=X:\\DATA\\CONTACT.mdb;Persist Security Info=True;Jet OLEDB:Database Password=4410210091";
      public static string SQL_1 = "SELECT pvnID, Province, Symbol FROM Sett_Post_Province";
      public static System.Data.DataTable GetTableForm(string _SQL, string strConn)
      {

          System.Data.DataSet ds = new System.Data.DataSet();
          System.Data.OleDb.OleDbConnection conn = new System.Data.OleDb.OleDbConnection(strConn);
          conn.Open();
          System.Data.OleDb.OleDbDataAdapter adapter2 = new System.Data.OleDb.OleDbDataAdapter(_SQL, conn);
          adapter2.Fill(ds);
          return ds.Tables[0];

      }
    }

private void Form2_Load(object sender, EventArgs e)
        {
            dataGridView1.DataSource = Database.GetTableForm(Database.SQL_1, Database.PostCodeConnectionString).DefaultView;
        }