จะเอาข้อความจาก Stored Procedures จะเขียน Code(VB.Net,C#) ยังไงครับ

	  try
            {

            string connetionString = null;
            SqlConnection connection;
            SqlDataAdapter adapter;
            SqlCommand command = new SqlCommand();
            DataSet ds = new DataSet();

            int i = 0;

            connetionString = "Data Source=servername;Initial Catalog=database;User ID=sa;Password=yourpassword";
            connection = new SqlConnection(connetionString);// connection

            connection.Open();
            command.Connection = connection;
            command.CommandType = CommandType.StoredProcedure;
            command.CommandText = "StoredProcedureName"; // ชื่อ Procedure
            adapter = new SqlDataAdapter(command);
            adapter.Fill(ds); // execute เสร็จ เก็บใส่ Dataset

            for (i = 0; i <= ds.Tables[0].Rows.Count - 1; i++)
            {
                MessageBox.Show(ds.Tables[0].Rows[i][0].ToString()); //Loop DataSet ออกมา
            }

            connection.Close();
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
            }

        Try
            Dim connetionString As String = "Data Source=servername;Initial Catalog=database;User ID=sa;Password=yourpassword"
            Dim connection As New SqlConnection(connetionString)
            Dim cmd As New SqlCommand

            cmd.CommandText = "StoredProcedureName"
            cmd.CommandType = CommandType.StoredProcedure
            cmd.Connection = connection

            connection.Open()

            Dim adapter As System.Data.SqlClient.SqlDataAdapter
            Dim ds As New DataSet

            adapter = New System.Data.SqlClient.SqlDataAdapter
            adapter.SelectCommand = cmd
            adapter.Fill(ds, "delivery")

            connection.Close()
            For i As Integer = 0 To ds.Tables(0).Rows.Count - 1
                Console.WriteLine(ds.Tables(0).Rows(i)(0).ToString())
            Next

        Catch ex As Exception
            Console.Write(ex.Message)
        End Try