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ขอโค้ดที่ทำให้Randomไม่ซ้ำกันทีครับ 1-36 กด36ครั้ง หรือ 36 ลูบ เลขที่เคยสุ่มออกแล้วต้องไม่ซ้ำกัน |
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Code (VB.NET)
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
End Sub
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim al As String, a1 As String, a2 As String, a3 As String, a4 As String, a5 As String, a6 As String, a7 As String, a8 As String, a9 As String, a10 As String
Dim rand As New Random
Dim num1 As Integer
num1 = rand.Next(1, 10)
MsgBox(num1)
a1 = a1
a2 = a2
a3 = a3
a4 = a4
a5 = a5
a6 = a6
a7 = a7
a8 = a8
a9 = a9
a10 = a10
End Sub
End Class
Tag : .NET
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| Date :
2016-12-02 11:05:26 |
By :
yainalove2015 |
View :
5757 |
Reply :
2 |
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Code (C#)
public class RandomNumber
{
public int StartNumber { set; get; }
public int EndNumber { set; get; }
private List<int> Numbers;
private Random r = new Random();
private void InitNumber()
{
for (int i = StartNumber; i <= EndNumber; i++)
this.Numbers.Add(i);
}
public void Start()
{
InitNumber();
}
public void Reset()
{
this.Numbers.Clear();
}
public int NextNumber()
{
int randomIndex = r.Next(this.Numbers.Count);
int number = this.Numbers[randomIndex];
this.Numbers.RemoveAt(randomIndex);
return number;
}
}
public void Print()
{
int start = 1, end = 36;
RandomNumber r = new RandomNumber();
r.StartNumber = 1;
r.EndNumber = 36;
r.Start();
for (int index = start; index < end; index++)
Console.WriteLine(r.NextNumber());
}
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| Date :
2016-12-02 12:05:29 |
By :
หวังว่าจะใช้ได้นะครับ |
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เพิ่ม Threading.Thread.Sleep เข้าไปเช่น
Code (VB.NET)
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load
For i As Integer = 1 To 36
Dim rn As New Random()
RichTextBox1.Text += vbCrLf & rn.Next(1, 36)
Threading.Thread.Sleep(100)
Next
End Sub
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| Date :
2016-12-02 12:12:31 |
By :
lamaka.tor |
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