$sql_color = "select b.color_name,b.pic_color_name,a.status_product
from product_color as a left join color as b on (a.color_id = b.id)
where a.product_id = '$id'";
Tag : - - - -
Date :
11 ส.ค. 2549 17:17:49
By :
kikkok
View :
2435
Reply :
3
No. 1
Guest
select .....
from table1 join table2
on table1. = table2.
join table3
on table1. หรือ table2. = table3.