ERROR แสดงข้อมูล โค้ดแสดงผลการค้นหาโดยเลือกการค้นจากเมนูลิสต์ $field คือเมนูลิสต์ของตัวนี้
<?php
mysql_connect($hostname_newsconn, $username_newsconn, $password_newsconn) or die(" MySQL !!! ");
mysql_select_db($database_newsconn);
if($field==""){
$sql="SELECT * FROM clipping_news INNER JOIN newspaper ON(clipping_news.newspaper_id=newspaper.newapaper_id) INNER JOIN groupnews ON (clipping_news.group_id=groupnews.group_id) INNER JOIN topic ON(clipping_news.topic_id=topic.topic_id)";
}else{
$sql = "SELECT * FROM clipping_news INNER JOIN newspaper ON(clipping_news.newspaper_id=newspaper.newspaper_id) INNER JOIN groupnews ON (clipping_news.group_id=groupnews.group_id) INNER JOIN topic ON(clipping_news.topic_id=topic.topic_id) WHERE $field like '%$key%'";
}
$result = mysql_query($sql);
$row=mysql_num_rows($result);
if(!empty($row)) {
while($fetcharr = mysql_fetch_array($result)) {
$clip_id = $fetcharr['clip_id'];
$clipping = substr($fetcharr['clipping'] , 0 , 50 );
$clippingfile=$fetcharr['clippingfile'];
$newspaper_id = $fetcharr['newspaper_id'];
$date = $fetcharr['date'];
$topic_id = $fetcharr['topic_id'];
$group_id = $fetcharr['group_id'];
}
echo "<tr><td><input type=checkbox name='$clip_id' onclick=CCA(this) ></td>
<td>$clip_id</td><td>$clipping</td><td>$clippingfile</td><td>$newspaper_id</td><td>$date</td><td>$topic_id</td>
<td>$group_id</td></tr>\n ";
}
?>
Date :
9 ก.พ. 2551 00:03:48
By :
Pro_Tae
ขอบคุณค่ะ อยากเลี้ยงข้าวตอบแทนจิงๆ
Date :
10 ก.พ. 2551 09:49:02
By :
apass
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