อยากได้code php ที่รวมการ insert +show +delete อยู่ในหน้าเดียวกันครับ

<?
//delete
if($id <> ''){
$sql = "delete from download_group where g_id='$id'";
$dbquery = mysql_db_query($db, $sql);
}

//insert
$name=$_POST[name];
if($name != ""){
$sql="insert into download_group(g_name) values('$name')";
mysql_query($sql) or die("cannot insert");
}
?>
<form name="form1" method="post" action="index.php?menu=agdownload">
<fieldset style="width:60%; margin:auto;">
<legend>เพิ่มข้อมูล Download</legend>
<table width="56%" border="0" align="center">

<tr>
<td width="25%"><div align="center">ชื่อ</div></td>
<td width="75%"><label>
<input name="name" type="text" id="name" size="30">
</label></td>
</tr>
<tr>
<td colspan="2"><div align="center">
<input type="submit" name="button" id="button" value="บันทึก">
</div></td>
</tr>
</table>
</fieldset>
</form>

<table width="80%" border="1" align="center" cellpadding="0" cellspacing="0">
<tr>
<td width="7%"><div align="center">ลำดับ</div></td>
<td width="79%"><div align="center">ชื่อ</div></td>
<td width="7%"><div align="center">แก้ไข</div></td>
<td width="7%"><div align="center">ลบ</div></td>
</tr>
<?
//include '../connect.php';
$sql="Select * From download_group order by g_id desc";
$result = mysql_query($sql);
$i=1;
While($row= mysql_fetch_array($result)){
$id=$row['g_id'];
$name=$row['g_name'];
?>
<script language="JavaScript">

function Conf<? echo "$id" ?>(object) {
if (confirm("Are you sure to Delete?") ==true) {
return true;
}
return false;
}

</script>
<?
if($i_ebook%2==0)
$bg="#ECFFFF";
else
$bg="FFFFFF";
?>
<tr>
<td><?=$i ?></td>
<td><?=$row[g_name] ?></td>
<td><div align="center"><a href="index.php?menu=aegdownload&id=<? echo $id; ?>"><img src="images/file_edit.png" width="16" height="16" border="0" /></a></div></td>
<td><div align="center"><a href="index.php?menu=agdownload&id=<? echo $id; ?>" onClick="return Conf<? echo "$id" ?>(this)"><img src="images/file_exclude.png" width="16" height="16" border="0" /></a></div></td>
</tr>
<?
$i=$i+1;
}
?>
</table>