ช่วยแนะนำการทำ link โดยมีค่าส่งจาก mysql_fetch_array ทีครับ

<form name="form1" method="post" action="show_data.php">
<center>
  <?php
$sql = "Select * from alldisease where db = '$part' order by id";
$query = mysql_query($sql);
while ($data = mysql_fetch_array($query)) 
{    
?>
  <table width="550" border="0">
    <tr>
      <td width="261">
<div align="left">
<?=$data['name']?>//<<<<<<<<<<<<<<<<<<<อยากได้ค่าจากตรงนี้ส่งไปอีกหน้านึงครับ
<?php 
$tbname = $data['enname'];
//echo $tbname;
?>
</div></td>
<td width="155">
  <div align="center">
  <?php
$host = "localhost";
$username = "root";
$pass = "root";
$dbname = "$part";//ฐานข้อมูลรวมชื่อโรค
$link = mysql_connect($host,$username,$pass) or die("Connect mysql ERROR!");
mysql_select_db($dbname,$link) or die("connect Database ".$dbname." Error");

mysql_query("SET character_set_client = tis620");
mysql_query("SET character_set_connection = tis620");
mysql_query("SET character_set_database = tis620");
mysql_query("SET character_set_results = tis620");
mysql_query("SET character_set_server = tis620");

	  $sumcheckbox = 0;
	  $strname = "select * from $tbname order by id";
	  $queryname = mysql_query($strname);
	  $numname = mysql_num_rows($queryname);
	  while ($dataname = mysql_fetch_array($queryname))
	  {
		$j = $dataname['id'];
		${checkbox.$j};
		$sumcheckbox = $sumcheckbox + ${checkbox.$j};
	  }
	  $total = (100*$sumcheckbox)/$numname;
	  if ($total==0)
	  {
	  echo "<font color = '#FFFF00'>ปลอดภัยจากโรคนี้</font>";
	  }
	  else
	  {
	  show($total);
	  }
	  ?>
  </div></td>
<td width="120"><div align="center"><a href = 'show_data.php' target='_blank'><font color = "#00FFFF">อ่านรายละเอียด</font></a></div></td>
    </tr>
<?php
} 
?>
  </table>
</center>
</form>