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นำข้อมูลจาก SESSION array มาแสดง ต่อจากกระทู้นี้นะครับ จะเอาข้อมูลออกมาแสดงยังไงหรือครับ ชี้แนะด้วยครับ |
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<?php
//แบบนี้ต้องจำว่า 0 กับ 1 เก็บค่าอะไร
$s = array();
$s["myCart"] = array();
$s["myCart"][] = array(1, 10);
$s["myCart"][] = array(2, 20);
foreach($s["myCart"] as $item){
echo '<br>',$item[0],'-',$item[1];
}
//แบบนี้จะอ่านเข้าใจง่ายกว่าครับ
$s = array();
$s["myCart"] = array();
$s["myCart"][] = array('id'=>1,'price'=>10);
$s["myCart"][] = array('id'=>2,'price'=>20);
foreach($s["myCart"] as $item){
echo '<br>',$item['id'],'-',$item['price'];
}
?>
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| Date :
2009-08-09 02:18:09 |
By :
num |
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Code (PHP)
$SESSION['array'] = $array;
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| Date :
2011-04-22 09:34:29 |
By :
ee |
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Code (PHP)
<? session_start();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<center>
<?php
include "connect.php";
$user =$_POST["user"];
$pass =$_POST["pass"];
$sql = "SELECT * FROM member where username='$user' and password= '$pass' ";
echo($sql);
$result = mysql_query($sql);
$rows = mysql_fetch_array($result);
$_SESSION['userid']= $rows["member_id"];
$_SESSION['name']=$rows["name"];
$_SESSION['image']=$rows["image"];
if($_SESSION['userid']== null){
echo("ชื่อผู้ใช้ หรือ รหัสผ่านของคุณไม่ถูกต้อง");
}else{
echo("ยินดีต้อนรับคุณ :").$_SESSION['username'];
}
?>
<META HTTP-EQUIV='Refresh' CONTENT='0; URL=index.php'>
</center>
</body>
</html>
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| Date :
2011-04-22 09:53:39 |
By :
ww |
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Code (PHP)
1
Code (ASP)
2
Code (C#)
3
Code (JavaScript)
4
Code (VBScript)
5
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| Date :
2011-04-22 09:54:52 |
By :
33 |
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