ทำยังไงถึงจะเรียกใช้ไฟล์ที่เราอัพโหลดไปได้ครับ คือผมทำโปรเจ็คเป็นประมาณให้เก็บพวกงานหรือแฟ้มข้อมูล

<?php
//global $HTTP_POST_FILES;
include("connect.php");
  $target = "upload/";
  $target = $target . basename( $_FILES['userfile']['name']); 
  //$username	= $_POST['username'];
  //$password	= base64_encode ($_POST['password']);
  //$realname = $HTTP_POST_FILES['userfile']['name'];
  $name=$_POST['name']; 
  $file=($_FILES['userfile']['name']); 
  mysql_connect("localhost", "root", "admin") or die(mysql_error()) ;
  mysql_select_db("regiss") or die(mysql_error()) ;
  mysql_query("INSERT INTO `upfileap` VALUES ('$name','$file')") ;
  if(move_uploaded_file($_FILES['userfile']['tmp_name'], $target))
	{
	echo "The file ". basename( $_FILES['uploadedfile']['name']);
	echo "<script>alert('?? upload complete ??');window.location='ap.php';</script>";
	}
else {
echo "<script>alert('?? upload not complete ??');window.location='ap.php';</script>";
}
?>

<?php
mysql_connect("localhost", "root", "admin") or die(mysql_error()) ;
		mysql_select_db("regiss") or die(mysql_error()) ;

		//Retrieves data from MySQL
		$data = mysql_query("SELECT * FROM upfileap") or die(mysql_error());

		//Puts it into an array
		while($info = mysql_fetch_array( $data ))
		{

		//Outputs the image and other data
		echo "<img src=http://www.yoursite.com/images/".$info['photo'] ."> <br>"; 
		echo "<b>Name:</b> ".$info['name'] . "<br> ";
}
?>

<?php
$name_del = $_GET[name];
$file_del = $_GET[userfile];
include("connect.php");
$sql="delete from upfileap where name='$name_del' ";
$result=mysql_db_query($dbname,$sql);
if($file_del<>""){
$file_del="uploadap/".$file_del;
if(file_exsits($file_del)){
unlink($file_del);
}
}
if($result){
echo "<H3>ลบโครงการเรียบร้อยแล้ว";
echo "[ <a href=ap.php>กลับหน้าหลัก</a>]";
}else{
echo "<H3>error:ไม่สามารถลบโครงการได้</H3>";
}
?>