ถามเรื่องส่งidไปอีกฟอร์ม โดย Class create table ก่อนอื่นผมต้องขอบคุณ Class create table

while($rs = mysql_fetch_assoc($result)) {
		$data[] = array(
			$rs['IDMember'],
			
			'<span class="name">'.$rs['Names'].'</span>',
			'<span class="name">'.$rs['Address'].'</span>',
			'<span class="name">'.$rs['Province'].'</span>',
			'<span class="name">'.$rs['Phone'].'</span>',
			'<span class="name">'.$rs['pwmember'].'</span>',

			'<a href="f_editmember.php:alert(\''.$rs['id'].'\');"><img src="images/icons/User-Edit.png" border="0" /></a>',
			'<a href="javascript:alert(\''.$rs['id'].'\');"><img src="images/icons/User-Cancel.png" border="0" /></a>');
	}

<?php 
include("config.php");

$sess_IDMember = $_GET['id'];

	$sql = "SELECT * FROM applymember WHERE IDMember='$sess_IDMember'"; 
mysql_query("SET NAMES 'UTF-8'"); 
	$result = mysql_query ($sql,$conn);
		
	$record = mysql_fetch_array($result,MYSQL_ASSOC);

		$IDMember = $_POST['IDMember'];
		$pwmember = $_POST['pwmember'];
		$Names = $_POST['Names'];
		$DayApply = $_POST['DayApply'];
		$People = $_POST['People'];
		$BirthDay = $_POST['BirthDay'];
		$Address = $_POST['Address'];
		$District = $_POST['District'];
		$Amper = $_POST['Amper'];
		$Province = $_POST['Province'];
		$Phone = $_POST['Phone'];
		$BookBank = $_POST['BookBank'];
		$BankAccount = $_POST['BankAccount'];
		$PostCode = $_POST['PostCode']; 

<table width="656" border="0">

    <tr>
      <td width="136" height="28"><div align="right">รหัสสมาชิก:</div></td>
      <td width="180"><?php echo $record['IDMember'];?></td>
      <td width="114"><div align="right">รหัสผู้แนะนำ:</div></td>
      <td width="241"><?php echo $record['Padvise'];?></td>
    </tr>
    <tr>
      <td height="28"><div align="right">รหัสผ่าน:</div></td>
      <td><input name="pwmember" type="text" id="pwmember" size="6" maxlength="6" value="<?php echo $record['pwmember'];?>"/></td>
      <td><div align="right">ชื่้อ-นามสกุล:</div></td>
      <td><?php echo $record['Nadvise'];?></td>
    </tr>
:
:
</table>


?>