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ถ้าผมจะเขียน code แบ่งหน้าแบบ Ajax ผมควรทำงัยครับงงอยู่ครับ |
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Code (PHP)
<?php
/*** By Weerachai Nukitram***/
/*** http://www.ThaiCreate.Com ***/
?>
<html>
<head>
<title>ThaiCreate.Com Ajax Tutorial</title>
</head>
<script language="JavaScript">
var HttPRequest = false;
function doCallAjax(Page) {
HttPRequest = false;
if (window.XMLHttpRequest) { // Mozilla, Safari,...
HttPRequest = new XMLHttpRequest();
if (HttPRequest.overrideMimeType) {
HttPRequest.overrideMimeType('text/html');
}
} else if (window.ActiveXObject) { // IE
try {
HttPRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
HttPRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {}
}
}
if (!HttPRequest) {
alert('Cannot create XMLHTTP instance');
return false;
}
var url = 'AjaxPHPListRecordPaging2.php';
var pmeters = 'myPage='+Page;
HttPRequest.open('POST',url,true);
HttPRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
HttPRequest.setRequestHeader("Content-length", pmeters.length);
HttPRequest.setRequestHeader("Connection", "close");
HttPRequest.send(pmeters);
HttPRequest.onreadystatechange = function()
{
if(HttPRequest.readyState == 3) // Loading Request
{
document.getElementById("mySpan").innerHTML = "Now is Loading...";
}
if(HttPRequest.readyState == 4) // Return Request
{
document.getElementById("mySpan").innerHTML = HttPRequest.responseText;
}
}
}
</script>
<body Onload="JavaScript:doCallAjax('1');">
<h1>My Customer</h1>
<span id="mySpan"></span>
</body>
</html>
Ref : Ajax List Record Paging/Pagination (PHP+MySQL & ASP+Access)
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| Date :
2010-01-30 19:31:32 |
By :
webmaster |
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ขอบคุณครับพี่วิน
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| Date :
2010-02-01 10:08:07 |
By :
ryuk |
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 Load balance : Server 01
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