ปัญหาการ Link ไป Lightbox ผมจะทำให้ปุ่มที่เกิดจาก input type='submit' ใน code บนให้มันเปิด Lightbox ด้วย code

<?php
	  if ($part_code and $pareto_chart and $start_date and $end_date)
	  {			  
			$data_table = "<table width='1600' border='2' cellpadding='2' cellspacing='2'>";
			$rows = get_reworkdata($part_code,$start_date,$end_date);	 	  
			$data_table .= "<tr bgcolor='orange'><th>No.</th>";
			foreach($rows as $time => $row)
			{
				foreach($row as $key => $value)
				{
					if (!preg_match("/(SNTime|OperatorID)/",$key))
					{	  
						$data_table .= "<th>$key</th>";
					}
				}
				break;
			}
			$data_table .= "</tr>\n"; 
			$no=0;
			foreach($rows as $time => $row)
			{
				$no++;
				if ($no&1) 
					$color='BISQUE';
				else
					$color='lightyellow';
				$data_table .= "<tr  bgcolor='$color'><td>$no</td>";
				foreach($row as $key => $value)
				{
					if ($key=='SN')
					{
						$data_table .= "<td><input type='submit' name='SN' value='$value'></td>";
					}
					elseif (!preg_match("/(SNTime|OperatorID)/",$key))
					{
						$values = explode("|",$value);
						$data_table .= "<td>";
						foreach($values as $val)
							$data_table .= "$val<br>";
						$data_table .= "</td>";
					}
				}
				$data_table .= "</tr>";
			}
			$data_table .= "</table>\n"; 
            }
  ?>

<a href = "javascript:void(0)" onclick = "document.getElementById('light').style.display='block';document.getElementById('fade').style.display='block'"></a>