สอบถาม error...Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource i

$result = mysql_query($sql);
?>
<table width="600" border="1" cellSpacing=0 cellPadding=2 >
  <tr>
    <td ><div align="center">ID Equipment</div></td>
    <td ><div align="center">Name</div></td>
    <td ><div align="center">Count</div></td>
    <td ><div align="center">Site</div></td>
  </tr>
<?

while ($dbarr = mysql_fetch_array($result) )  <<<<<<<<<< บรรทัดที่ 59
{
?>
		<tr>
    <td align="center"><? echo $dbarr['ID']; ?></td>
    <td align="center"><? echo $dbarr['Name']; ?></td>
    <td align="center"><? echo $dbarr['Count']; ?></td>
    <td align="center"><? echo $dbarr['type']; ?></td>
  </tr>
<? } ?>
</table>
<?
mysql_close($link);
?>