พี่ค่ะ ขอโค้ด แก้ไขรูปภาพ แล้วบันทึกลงฐานข้อมูลหน่อยค่ะ

 <form action="Update.php?id=<? echo $id ?>" method="post" id="form1" enctype="multipart/form-data" >
<table>
    <tr>
          <td><div align="left">Image</div></td>
          <td> <div align="left"><? echo "<img src='Path old image' width='90' height='100'>";?><br />
            <input name="Images_Con" type="file" id="Images_Con" size="20" maxlength="50"/>
            <span class="style15"><font color="#FF0000">&lt;<span class="style20"><font color="#FF0000">Upload image </font></span><font color="#FF0000">.gif </font><span class="style20"><font color="#FF0000">or</font></span><font color="#FF0000"> .jpg</font>&gt;</font></span></div></td>
          </tr>
   <tr>
          <td colspan="2"><div align="center">
            <label>
              <input type="submit" name="Submit" value="SAVE" />
              </label>
            <label>
              <input type="reset" name="Submit2" value="CANCLE" />
              </label>
            </div></td>
          </tr>
</table></form>

   $data = mysql_query("select Image_Pro from product where ID_Pro = '$id'");

if(trim($_FILES["Images_Con"]["tmp_name"]) != ""){
				
        if(empty($_FILES["Images_Con"]["tmp_name"])){  
			  $old_pro= $pro[0];
        }else{	

	$Images_Con=$_FILES["Images_Con"]["tmp_name"];
						
	$type = getimagesize($Images_Con); 
	if($type[2] == 1) { 
													$image = $date."_img.gif";
	} else if($type[2] == 2) { 
													$image = $date."_img.jpg";
	}
							
	copy($Images_Con, "images_product/$image"); 
	chmod("images_product/$image", 0664);
								
											$Images_Con=$image;
          }
}

if($Images_Con!="" or !empty($Images_Con) ){
	$sql=mysql_query("UPDATE product SET  Image_Pro = '$Images_Con' WHERE ID_Pro ='$id'");
}
				
if($Images_Con=="" or empty($Images_Con)){
	$sql=mysql_query("UPDATE product SET  Image_Pro = '$old_pro'    WHERE ID_Pro ='$id'");
}