โค๊ด Upload ครับ มีปัญหาคือ ผมจะอัพโหลดภาพและข้อมูล field อื่นลง Data Base ด้วย

<form action="person_up.php" method="POST" name="form1" enctype="multipart/form-data">
  <table width="302" align="center" cellpadding="1" cellspacing="2">
    <tr>
      <td colspan="2">Add:</td>
    </tr>
    <tr>
      <td width="125">ชื่อ</td>
      <td width="165"><label for="degree"></label>
      <input type="text" name="name" id="textfield2" /></td>
    </tr>
    <tr>
      <td>การศึกาษา</td>
      <td><label for="position"></label>
      <input type="text" name="degree" id="textfield3" /></td>
    </tr>
    <tr>
      <td>ตำแหน่ง</td>
      <td><label for="email"></label>
      <input type="text" name="position" id="textfield4" /></td>
    </tr>
    <tr>
      <td>E-mail</td>
      <td><label for="textfield5"></label>
      <input type="text" name="email" id="textfield5" /></td>
    </tr>
    <tr>
      <td>รูปส่วนตัว</td>
      <td><label for="textfield6"></label>
      <input type="file" name="fileUpload">
      <input name="btnSubmit" type="submit" value="Submit"></td>
    </tr>
    <tr>
      <td>&nbsp;</td>
      <td>&nbsp;</td>
    </tr>
  </table>
</form>

<? 
session_start();
 
$hostname_con_stru = "localhost";
$database_con_stru = "stru_db";
$username_con_stru = "root";
$password_con_stru = "097057653";
$name=$_POST[name];
$degree=$_POST[degree];
$position=$_POST[position];
$email= $_POST[email];
$fileUpload = $_POST[fileUpload];

if(copy($_FILES["fileUpload"]["tmp_name"],"upload/".$_FILES["fileUpload"]["name"]))   
{   
mysql_connect("localhost","root","097057653") or die (mysql_error());   
mysql_select_db("stru_db");   
$strSQL = "INSERT INTO personal(person_id,name,degree,position,email,fileUpload)
		   VALUES('','$name','$degree','$position','$email','$fileUpload')";  
$strSQL .="(fileUpload,Picture) VALUES ('".$_POST["txtGalleryName"]."','".$_FILES["fileUpload"]["name"]."')";   
mysql_query($strSQL);   
echo "<meta http-equiv='refresh' content='1 ;url=personal_list.php'>";   
mysql_close();   
}   

if($fname)
{
	mysql_db_query($dbname,$sql);
}

?>