พอเปิดหน้ามา ก็ให้เช็คค่า ของ check box ถ้าไม่มีการ checked ก็ไม่ต้องโชว์ข้อมูล จะแก้โค้ดอันนี้ยังไงคะ JQUERY

$cols = array(
	"aa"=>"Column AA", 
	"bb"=>"Column BB", 
	"cc"=>"Column CC", 
	"dd"=>"Column DD", 
	"ee"=>"Column EE", 
	"ff"=>"Column FF", 
	"gg"=>"Column GG", 
	"hh"=>"Column HH", 
	"ii"=>"Column II", 
);

<script type="text/javascript">
	$(document).ready(function toggle(id){
		eval("if($('#" + id + "').is(':checked')){ $('td[abbr=\"" + id + "\"]').show(); }else{ $('td[abbr=\"" + id + "\"]').hide(); }");
	});
</script>

echo '<input type="checkbox" id="' . aa . '" checked="checked" onclick="toggle(\'' . aa . '\')" /><label for="' . aa . '">Column AA</label><br/>' . "\n";
echo '<input type="checkbox" id="' . bb . '" checked="checked" onclick="toggle(\'' . bb . '\')" /><label for="' . bb . '">Column BB</label><br/>' . "\n";
echo '<input type="checkbox" id="' . cc . '" checked="checked" onclick="toggle(\'' . cc . '\')" /><label for="' . cc . '">Column CC</label><br/>' . "\n";
echo '<input type="checkbox" id="' . ii . '"  onclick="toggle(\'' . ii . '\')" /><label for="' . ii . '">Column II</label><br/>' . "\n";