เรียนถามท่านผู้รู้ ต้องการเอาค่าที่เก็บไว้ใน arrayมาแสดงในตารางทำไงค่ะ ช่วยแนะนำหน่อยค่ะ

<?php
		
		$firstmonth =  $omonth;
		$firstyear =  $oyear;
		$tmonth = $firstmonth;
		$tyear =  $firstyear;		
		$jobtype = array();
		for ($i=1; $i<=12; $i++) {
			if ($tmonth == 13 ) { 
				$tmonth =  1;
				$tyear = $tyear + 1;
				}
			$jobtype [$i][1] = $tmonth;   //1 ==> month
			$jobtype [$i][2] = $tyear;      // 2 ==> Year 
			$jobtype [$i][3] = 0.00;         //  3 ==>  jobtype_a
			$jobtype[$i][4] = 0.00;        //  4 ==>  jobtype_b
			$jobtype[$i][5] = 0.00;         //  5 ==>  jobtype_c
			$jobtype[$i][6] = 0.00;         //  6 ==>  jobtype_d
			$jobtype[$i][7] = 0.00;        //  7 ==>  jobtype_direct
			$jobtype[$i][8] = 0.00;      //  8 ==>  jobtype_indirect
			$tmonth = $tmonth + 1;
			}		

		$sql ="SELECT JobType, year(TransDate), month(TransDate), sum(Amount)
					FROM cashflow 
					WHERE ProjectCode ='$projectcode'
					AND TypeCode = 'P'
					GROUP BY  JobType, year(TransDate), month(TransDate)
					Order by  JobType ASC, year(TransDate) ASC, month(TransDate)  ASC ";
		
		//$cash_plain  

		$temp = mysql_query($sql) or die("<h1> Error : $sql</h1>");
		$countcash = mysql_num_rows($temp);
		while ($data = mysql_fetch_array($temp,MYSQL_BOTH)) {
			$cash_type = $data["JobType"];
			$tmonth =  $data["2"];
			$tyear =  $data["1"];
			if ($firstyear == $tyear) { $i = ($tmonth - $firstmonth) + 1;}
			if ($firstyear < $tyear) { $i = (12 - $firstmonth)+1 + $tmonth;}
			switch ($cash_type) {
				case "A"  :
					$jobtype[$i][3] = $data["3"];
					break;
				case "B"  :
					$jobtype[$i][4] = $data["3"];
					break;					
				 case "C"  :
					$jobtype[$i][5] = $data["3"];
					break;					
				case "D"  :
					$jobtype[$i][6] = $data["3"];
					break;					
			}
		}

		$sql ="SELECT ExpenseType, year(DateExpense) ,month(DateExpense) ,  sum(Amount)
		FROM expense_cost
		WHERE ProjectCode = '$projectcode'
		GROUP BY ExpenseType,  year(DateExpense), month(DateExpense)
		Order by ExpenseType ASC, year(DateExpense) ASC, month(DateExpense) ASC ";

		$temp2 =mysql_query($sql) or die("<h1> Error : $sql</h1>");
		$countexpense = mysql_num_rows($temp2);
		while ($data2 = mysql_fetch_array($temp2,MYSQL_BOTH)) {
			$tmonth =  $data2["2"];
			$tyear =  $data2["1"];
			if ($firstyear == $tyear) { $i = ($tmonth - $firstmonth) + 1;}
			if ($firstyear < $tyear) { $i = (12 - $firstmonth)+1 + $tmonth;}	
			 if ($data2["ExpenseType"] == "D") {$jobtype[$i][7] = $data2["3"] ;}
			 if ($data2["ExpenseType"] == "I") {$jobtype[$i][8] = $data2["3"] ;}
		}	
// Display header 12 month	
	print "<br/>"."<font size='2'>".เดือนปี."<br/>"."</font>";
		for ($i=1; $i <= 12; $i++) {
			echo $jobtype[$i][1]." / ".$jobtype[$i][2]."---";
			}
	

		print "<br/>"."<font size='2'>".ค่าใช้จ่ายในการบริหารงาน."<br/>"."</font>";
		for ($i=1; $i <= 12; $i++) {
			echo $jobtype[$i][3]."--------";
			}
			print "<br/>";
		for ($i=1; $i <= 12; $i++) {
			echo $jobtype[$i][4]."--------";
			}		
			print "<br/>";
		for ($i=1; $i <= 12; $i++) {
			echo $jobtype[$i][5]."--------";
			}
			print "<br/>";
				for ($i=1; $i <= 12; $i++) {
			echo $jobtype[$i][6]."--------";
			}		
			
		print "<br/>"."<font size='2'>".ค่าใช้จ่ายในการบริหารงานโครงการโดยทางตรง."<br/>"."</font>";
		for ($i=1; $i <= 12; $i++) {
			echo $jobtype[$i][7]."--------";
			}
		
		print "<br/>"."<font size='2'>".ค่าใช้จ่ายในการบริหารงานโครงการโดยทางอ้อม."<br/>"."</font>";	
		for ($i=1; $i <= 12; $i++) {
			echo $jobtype[$i][8]."--------";
			}		

		print  "<br/>";		
		
?>