$sql = "SELECT * FROM st WHERE st.date BETWEEN '$txt_search' AND '$txt_search1'";
$sql .= " JOIN st1 ON (st.nost=st1.nost) ";
$sql .= " JOIN st2 ON (st.nost=st2.nost) ";
$result = mysql_query($sql);
while($r=mysql_fetch_array($result))>>>>> มานพ้องที่บรรทัดนี้ตลอดเลยช่วยด้วยค่ะ.........
{
$usershow=$r['usershow'];
$date=$r['date'];
$description1 =$r['description1'];
$nost=$r['nost'];
มานพ้องว่า
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\AppServ\www\stock\showstest.php on line 28
ขอบรบกวนเวลาผู้รู้ด้วยจ้า.....