ข้อมูลไม่ออกจะทำยังไงดีค่ะ ตอนนี้ไใม่รู้จะทำไงแล้วค่ะ รบกวนท่านผู้รู้ช่วยที

<form name="form" id="form" method="post">
   ประเภทคดี
	<label>
        <select name="jumpMenu" id="jumpMenu" onchange="MM_jumpMenu('parent',this,0)">
        <?
			include ("connectDB.php");
			mysql_query ("SET NAMES utf8") or die (mysql_errno());
           	$result = mysql_query("SELECT DISTINCT Type FROM cases");
           	while($row = mysql_fetch_array($result)){
        ?>
        	<option value="<? echo $row['Type'] ?>"><? echo $row['Type'] ?></option>
         <? } ?>
        </select>
      </label>
    </form>
	<p></p>
      <?
	  	include ("datethai.php");
	  	include ("connectDB.php");
		$type = $_REQUEST["Type"];
		$sql = "SELECT * FROM `cases` Where Type = '".$_POST["jumpMenu"]."'";
		$result = mysql_query($sql);
		echo"<table width='90%' border='1' style='border-collapse: collapse' bordercolor='#A59A1B'  bgcolor='#D3BC38' ><tr align='center'>
			<td><b>เลขที่คดี</b></td>
			<td><b>วันที่</b></td>
			<td><b>ประเภทคดี</b></td>
			<td><b>รายละเอียด</b></td>
			<td><b>ผู้ต้องหา</b></td>
			<td><b>เจ้าหน้าที่ผู้รับผิดชอบ</b></td>
			</tr>";
		while($row=mysql_fetch_array($result)){
			$caseid = $rows["CaseID"];	
			$casedate = DateThai($rows["CaseDate"]);
			$type = $rows["Type"];			
			$description = $rows["Description"];
			$captive = $rows["Captive"];	
			$casepolice = $rows["CasePolice"];	
		echo "<tr bgcolor='#D3BC38' align='center'>";
			echo "<td>$caseid</td>";
			echo "<td>$casedate</td>";	
			echo "<td>$type</td>";
			echo "<td><a href=\"ShowCase1.php?CaseID=$caseid\" target=\"$caseid\">คลิก</td>";
			echo "<td>$captive</td>";
			echo "<td>$casepolice</td>";
			echo "</td></form></tr>";
		}
		echo "</table>";
?>