ถ้าตาม code ของผมนี้ จะส่งค่า จากjava ไป php ได้อย่างไงครับ
ถ้าตามcodeของผมนี้ จะส่งค่า จากjava ไป php ได้อย่างไงครับCode (PHP) <html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>TEST AJAX</title>
<script type="text/javascript" src="myajax.js"></script>
<script language="javascript">
function display01(data) {
var objDiv = document.getElementById("targetDiv");
var php ="<?
include "../config/config.in.php";
echo "<option selected value=''>---โปรดเลือก---</option>";
//$ip=$_POST['ip'];
$strSQL = "SELECT * FROM course_subject where ClassID='A'";
$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
while($objResult = mysql_fetch_array($objQuery))
{
echo "<option value='".$objResult["SubID"]."'>".$objResult["SubName"].'('.$objResult["SubID"].')'."</option>";
}
?>";
objDiv.innerHTML = php;
}
function display04(strBookDetails) {
var objDiv = document.getElementById("targetDiv4");
objDiv.innerHTML = strBookDetails;
}
function select01(data){
postDataReturnText('list01', 'ip=' + data, display01);
}
function select04(data){
postDataReturnText('listbook', 'ip=' + data, display04);
}
</script>
</head>
<body>
test01
<table>
<tr>
<td><font size="2">ประเภทหลักสูตร:</font></td>
<td><font size="2">
<select name="02" onChange = "select01(this.value),select04(this.value)">
<option selected value="">---โปรดเลือก---</option>
<?
$strSQL = "SELECT * FROM course_classlevel ORDER BY ClassSort ASC ";
$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
while($objResult = mysql_fetch_array($objQuery))
{
?>
<option value="<?=$objResult["ClassID"];?>"><?=$objResult["ClassName"].'('.$objResult["ClassID"].')';?></option>
<?
}
?>
</select></font></td>
</tr>
<tr>
<td><font size="2">หลักสูตร:</font></td>
<td><font size="2">
<select name="03" id="targetDiv" onChange = "select02(this.value)">
<option selected value="">---โปรดเลือก---</option>
</select></font></td>
</tr>
<tr>
<td><font size="2">วิชา:</font></td>
<td><font size="2">
<select name="04" id="targetDiv2" OnChange="resutName(this.value);">
<option selected value="">---โปรดเลือก---</option>
</select></font></td>
</tr>
</table>
<br />
<div id="targetDiv4"></div>
</body>
</html>
Tag PHP, MySQL, JavaScript, Ajax, CakePHP, JAVA
Date :
2013-04-25 16:06:00By :
kissoverView :
1060Reply :
2
You cannot pass variable values from the current page javascript to the current page PHP code... PHP code runs at the server side and it doesn't know anything about what is going on on the client side.http://stackoverflow.com/questions/1917576/how-to-pass-javascript-variables-to-php
Date :
2013-04-25 16:34:19By :
popnakub
Date :
2013-04-25 21:10:53By :
mr.win
Server 00
Load balance : Server 00
