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การคำนวนค่าในอารเรย์ที่คำนวนไว้เเล้ว มาเก็บ ค่าเเล้วไห้ออกมาเป็นผลรวม ต้องทำอย่างไรหรือ ครับ เเนะนำด้วย ครับ |
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แบบนี้ได้ป่าวครับ ลองดู
<?
$sql_show = "select * from depreciation where category='1' && company_id = '$company_id' ";
mysql_query("SET NAMES UTF8");
$result_show = mysql_query($sql_show) or die( mysql_error());
$num = mysql_num_rows($result_show);
$i = '1';
while($row = mysql_fetch_array($result_show)){
$date_num_day = (( strtotime($date_end) - strtotime($row['date_buy']) ) / ( 60 * 60 * 24 )); // หาความต่างของวัน
?>
<tr>
<td><? echo $i;?></td>
<td><? echo $row['name'];?></td>
<td><? echo $row['date_buy'];?></td>
<td><? echo ceil($date_num_day);?></td>
<td><? echo $row['price'];?></td>
<td><? echo $row['rate']*10;?> %</td>
<td><? echo "";?></td>
<td><? echo $total = number_format(($row['price']*($row['rate']/10)*ceil($date_num_day))/$num_day_year,2);?></td>
<td><? echo $total = number_format(($row['price']*($row['rate']/10)*ceil($date_num_day))/$num_day_year,2);?></td>
<td><?PHP $input_array[] = $row['price']-extract_int($total); #ให้ตัวแปร $input_array เก็บค่าเป็น Array ?></td>
</tr>
<? $i++ ;?>
<? } ?>
<?php
echo $sum_of_input_array = array_sum ( $input_array ); #แสดงผลรวม
?>
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Date :
2013-08-14 17:24:03 |
By :
arm8957 |
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Load balance : Server 02
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