ช่วยหน่อยครับ Column 'Column_Name' in where clause is ambiguous

<form action="<?=$_SERVER['SCRIPT_NAME'];?>" method="POST" name="form1">
<table bgcolor="#FFECF5" width="490" cellpadding="0" cellspacing="0">
<tr>
<td align="right" width="400">ค้นหา
<select name="search1" id="search1">
	<option value="ID_Rec" <? if($_POST["search1"]=="ID_Rec"){echo "selected";}?>>รหัสการจอง</option>
    <option value="ID_Cus" <? if($_POST["search1"]=="ID_Cus"){echo "selected";}?>>รหัสลูกค้า</option>
    <option value="Tel_Cus" <? if($_POST["search1"]=="Tel_Cus"){echo "selected";}?>>เบอร์โทรศัพท์</option>
    <option value="Name_Cus" <? if($_POST["search1"]=="Name_Cus"){echo "selected";}?>>ชื่อลูกค้า</option>
</select>    
คำสำคัญ<input name="txtKeyword" type="search" size="20" id="txtKeyword" value="<?=$_POST["txtKeyword"];?>" onKeyPress="return chspace()"></td>
<td width="74" align="left"><input type="image" value="submit" src="images/Search-icon32px.png" alt="ค้นหา"></td>
</tr>
</table>
</form>
<br>        
<?
$textsearch=$_POST['txtKeyword'];
$search1=$_POST['search1'];
include "connect.php";
$sql = "SELECT customer.*,receipt.* from customer inner join receipt on customer.ID_Cus=receipt.ID_Cus WHERE 
(customer.Name_Cus and $search1 LIKE '%".$textsearch."%' or customer.ID_Cus and $search1 LIKE '%".$textsearch."%' 
or customer.Tel_Cus and $search1 LIKE '%".$textsearch."%'or receipt.ID_Rec and $search1 LIKE '%".$textsearch."%')";