รบกวนสอบถามการ Select ข้อมูล แบบไม่เปลี่ยนหน้า โชว์ตั้งงแต่ตอนแรก นะครับ

<script language="JavaScript">
     var HttPRequest = false;

     function doCallAjax(ID) {

      HttPRequest = false;
      if (window.XMLHttpRequest) { // Mozilla, Safari,...
       HttPRequest = new XMLHttpRequest();
       if (HttPRequest.overrideMimeType) {
        HttPRequest.overrideMimeType('text/html');
       }
      } else if (window.ActiveXObject) { // IE
       try {
        HttPRequest = new ActiveXObject("Msxml2.XMLHTTP");
       } catch (e) {
        try {
           HttPRequest = new ActiveXObject("Microsoft.XMLHTTP");
        } catch (e) {}
       }
      } 
      
      if (!HttPRequest) {
       alert('Cannot create XMLHTTP instance');
       return false;
      }
    
      var url = 'checkpoint.php';
      var pmeters = "league=" + ID ;


      HttPRequest.open('POST',url,true);

      HttPRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
      HttPRequest.setRequestHeader("Content-length", pmeters.length);
      HttPRequest.setRequestHeader("Connection", "close");
      HttPRequest.send(pmeters);
      
      
      HttPRequest.onreadystatechange = function()
      {

        if(HttPRequest.readyState == 3)  // Loading Request
        {
          document.getElementById("mySpan").innerHTML = "..";
        }

        if(HttPRequest.readyState == 4) // Return Request
        {
          if(HttPRequest.responseText == 'Y')
          {
            window.location = 'index.php';
            return ID;
          }
          else
          {
            document.getElementById("mySpan").innerHTML = HttPRequest.responseText;
          }
        }
        
      }
     }
  </script>

<ul name="league" id="league">
              		<input type="hidden" name="id" id="id" size="30"  OnChange="JavaScript:doCallAjax();" value="1"/>
                  <?php
                  $query_list=mysql_query("Select * From league where l_delete=0 order by lid");
                  while($sl < mysql_num_rows($query_list)){
                  $arrL= mysql_fetch_array($query_list);
                  ?>
                <li><a href="JavaScript:doCallAjax('<?=$arrL["lid"];?>');" ><?php echo $arrL['lnamethai'] ?></a></li>
               
                  <?php
                  $sl++;
                  }
                  ?>
                  </ul>