ถามเรื่องการส่งค่า List menu ในหน้าเดียวกัน (ทำยังไงครับ)

<select name="employee" id="employee" class="styledselect_form_1" >
			<option value="">เลือก</option>
			<?php
			$sql = "SELECT * FROM employee ORDER BY EmployeeID ASC";
			$query = mysqli_query($conn,$sql)or die("Error: ".mysqli_error($conn));
			while($result = mysqli_fetch_array($query,MYSQLI_ASSOC))
			{
			?>
			<option value="<?php echo $result["EmployeeID"];?>"><?php echo $result["FirstName"];?>      <?php echo $result["LastName"];?></option>

			<?php
			}
			?>
		  </select>          </td>

          <td>งานค้าง</td>
		  <td><?php 
			$sql1=" SELECT COUNT(*) FROM job WHERE (EmployeeIDRepair = '".$result["EmployeeID"]."') AND (Status = 'Receive' OR Status = 'Pending')";
			$query = mysqli_query($conn,$sql1)or die("Error: ".mysqli_error($conn));
			$result1 = mysqli_fetch_array($query,MYSQLI_ASSOC);
			echo $result1["COUNT(*)"];
			?></td>