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ต้องการ นำค่าจาก Javascript มาใช้ในส่วนของ php ต้องดึงค่ายังไงครับ |
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Code (PHP)
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>JPEGCam Test Page: Image Resize</title>
<meta name="generator" content="TextMate http://macromates.com/">
<meta name="author" content="Joseph Huckaby">
<!-- Date: 2008-03-15 -->
</head>
<body>
<table><tr><td valign=top>
<h1>JPEGCam Test Page with Image Resize</h1>
<h3>Demonstrates resizing the image from 320x240 down to 160x120 before upload.</h3>
<!-- First, include the JPEGCam JavaScript Library -->
<script type="text/javascript" src="webcam.js"></script>
<!-- Configure a few settings -->
<script language="JavaScript">
webcam.set_api_url( 'test.php' );
webcam.set_quality( 90 ); // JPEG quality (1 - 100)
webcam.set_shutter_sound( true ); // play shutter click sound
</script>
<!-- Next, write the movie to the page at 320x240, but request the final image at 160x120 -->
<script language="JavaScript">
document.write( webcam.get_html(320, 240, 160, 120) );
</script>
<!-- Some buttons for controlling things -->
<br/><form>
<input type=button value="Configure..." onClick="webcam.configure()">
<input type=button value="Take Snapshot" onClick="take_snapshot()">
</form>
<!-- Code to handle the server response (see test.php) -->
<script language="JavaScript">
webcam.set_hook( 'onComplete', 'my_completion_handler' );
function take_snapshot() {
// take snapshot and upload to server
document.getElementById('upload_results').innerHTML = '<h1>Uploading...</h1>';
webcam.snap();
}
function my_completion_handler(msg) {
// extract URL out of PHP output
if (msg.match(/(http\:\/\/\S+)/)) {
var image_url = RegExp.$1;
// show JPEG image in page
document.getElementById('upload_results').innerHTML =
'<h1>Upload Successful!</h1>' +
'<h3>JPEG URL: ' + image_url + '</h3>' +
'<img src="' + image_url + '">';
// reset camera for another shot
webcam.reset();
}
else alert("PHP Error: " + msg);
}
</script>
</td><td width=50> </td><td valign=top>
<div id="upload_results" style="background-color:#eee;"></div>
</td></tr></table>
</body>
</html>
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| Date :
2016-05-12 14:37:19 |
By :
nayrock |
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Code (PHP)
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>JPEGCam Test Page: Image Resize</title>
<meta name="generator" content="TextMate http://macromates.com/">
<meta name="author" content="Joseph Huckaby">
<!-- Date: 2008-03-15 -->
</head>
<body>
<table><tr><td valign=top>
<h1>JPEGCam Test Page with Image Resize</h1>
<h3>Demonstrates resizing the image from 320x240 down to 160x120 before upload.</h3>
<!-- First, include the JPEGCam JavaScript Library -->
<script type="text/javascript" src="webcam.js"></script>
<!-- Configure a few settings -->
<script language="JavaScript">
webcam.set_api_url( 'test.php' );
webcam.set_quality( 90 ); // JPEG quality (1 - 100)
webcam.set_shutter_sound( true ); // play shutter click sound
</script>
<!-- Next, write the movie to the page at 320x240, but request the final image at 160x120 -->
<script language="JavaScript">
document.write( webcam.get_html(320, 240, 160, 120) );
</script>
<!-- Some buttons for controlling things -->
<br/><form>
<input type=button value="Configure..." onClick="webcam.configure()">
<input type=button value="Take Snapshot" onClick="take_snapshot()">
</form>
<!-- Code to handle the server response (see test.php) -->
<script language="JavaScript">
webcam.set_hook( 'onComplete', 'my_completion_handler' );
function take_snapshot() {
// take snapshot and upload to server
document.getElementById('upload_results').innerHTML = '<h1>Uploading...</h1>';
webcam.snap();
}
function my_completion_handler(msg) {
// extract URL out of PHP output
if (msg.match(/(http\:\/\/\S+)/)) {
var image_url = RegExp.$1;
// show JPEG image in page
document.getElementById('upload_results').innerHTML =
'<h1>Upload Successful!</h1>' +
'<h3>JPEG URL: ' + image_url + '</h3>' +
'<img src="' + image_url + '">';
// reset camera for another shot
webcam.reset();
}
else alert("PHP Error: " + msg);
}
</script>
</td><td width=50> </td><td valign=top>
<div id="upload_results" style="background-color:#eee;"></div>
</td></tr></table>
</body>
</html>
ขอบคุณมากนะครับแต่มันก็งงๆครับคือผมอ่อนมากเลยครับ อยากนำค่าของ image_url มาใช้ดังด่านล่างอะครับ ไม่รู้เขียนไงอะครับ
<p
$piclink = image_url ;
echo $piclink;
p>
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| Date :
2016-05-12 14:53:29 |
By :
nayrock |
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ช่วยด้วยครับบบ ทำไม่ได้โดนไล่ออกแน่
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| Date :
2016-05-12 15:26:14 |
By :
nayrock |
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เอาค่าใส่ input txtbox ส่งค่าไปดำเนินการต่อ
document.getElementById("xxx1").value = image_url ; //ใส่ก่อนบรรทัด 53
<input type="text" id="xxx1" value=""> อันนี้ก็ไว้ตรงไหนก็ว่าไป
ถ้ามันส่งค่ามาแสดงได้ อาจจะเห็นหนทางอ่ะ 
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| Date :
2016-05-12 16:22:38 |
By :
Kin-Kee |
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