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I have paging problems with INNER JOIN table of sqlsrv with php.

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rainkv

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บทความ ( 0 )

I have 2 tables as follows:
Table1: Studen(Studen_ID, Name, Class_ID)
Table2: Class(Class_ID,ClassName)
- When I INNER JOIN these 2 tables together, it works fine:

Quote:
$stmt = "SELECT Studen_ID,Name,ClassName FROM Studen
INNER JOIN Class
ON Studen.Class_ID=Class.Class_ID
WHERE TenNhanVien LIKE '%".$strKeyword."%' ";

- But when I perform paging, report an error:

Quote:
$stmt = " SELECT Name,Studen_ID FROM
(SELECT ROW_NUMBER() OVER(ORDER BY Name) AS RowID,Name,Studen_ID FROM Studen WHERE Name LIKE '%".$strKeyword."%'

) AS Studen_ID
WHERE Studen_ID.RowID > $row_start AND Studen_ID.RowID <= $row_end

";

-Class name does not display data.
Hope the helping.
Thank you very much!

Tag : PHP

Date : 2019-08-24 15:31:48

By : rainkv

View : 767

Reply : 4

No. 1

Chaidhanan

โพสกระทู้ ( 9,586 )
บทความ ( 2 )

$stmt = " SELECT Name,Studen_ID FROM
(SELECT ROW_NUMBER() OVER(ORDER BY Name) AS RowID,Name,Studen_ID FROM Studen WHERE Name LIKE '%".$strKeyword."%'

) AS Studen_ID
WHERE Studen_ID.RowID > $row_start AND Studen_ID.RowID <= $row_end

It is conflict blue and red

Code (PHP)

$stmt = " SELECT Name,Studen_ID 
FROM(
  SELECT ROW_NUMBER() OVER(ORDER BY Name) AS RowID,Name,Studen_ID 
  FROM Studen WHERE Name LIKE '%".$strKeyword."%'
) AS tmp
WHERE tmp.RowID > $row_start AND tmp.RowID <= $row_end
";

Please try
$result = sqlsrv_query(........) or die( print_r( sqlsrv_errors(), true));

You can see error and Notice for resolve it by yourself.

Date : 2019-08-24 16:20:51

By : Chaidhanan

No. 2

rainkv

โพสกระทู้ ( 0 )
บทความ ( 0 )

Thanks for the reply, but I mean the classnam field does not display data. Hope the helping.
Thank you!
Class name does not display data.

My code:

Quote:
<html>
<head>
<title>Trâm Anh Danh sách nhân viên</title>
</head>
<body>
<?php
ini_set('display_errors', 1);
error_reporting(~0);

$strKeyword = null;

if(isset($_POST["txtKeyword"]))
{
$strKeyword = $_POST["txtKeyword"];
}
if(isset($_GET["txtKeyword"]))
{
$strKeyword = $_GET["txtKeyword"];
}
?>
<form name="frmSearch" method="post" action="<?php echo $_SERVER['SCRIPT_NAME'];?>">
<table width="599" border="0">
<tr>
<th>Nhập tên nhân viên:
<input name="txtKeyword" type="text" id="txtKeyword" value="<?php echo $strKeyword;?>">
<input type="submit" value="Tìm kiếm"></th>
</tr>
</table>
</form>
<?php
$serverName = "QGSLUOU6NK9BNBY\SQLEXPRESS";
$userName = "sa";
$userPassword = "12345";
$dbName = "PHP_TEST";

$connectionInfo = array("Database"=>$dbName,"characterSet"=>"UTF-8", "UID"=>$userName, "PWD"=>$userPassword, "MultipleActiveResultSets"=>true);

$conn = sqlsrv_connect( $serverName, $connectionInfo);

if( $conn === false ) {
die( print_r( sqlsrv_errors(), true));
}

$stmt = "SELECT Studen_Id,Name,ClassName FROM Studen
INNER JOIN Class
ON Studen.Class_Id=Class.Class_Id
WHERE Name LIKE '%".$strKeyword."%' ";

$params = array();
$options = array( "Scrollable" => SQLSRV_CURSOR_KEYSET );
$query = sqlsrv_query( $conn, $stmt , $params, $options );

$num_rows = sqlsrv_num_rows($query);

$per_page = 25; // Per Page
$page = 1;

if(isset($_GET["Page"]))
{
$page = $_GET["Page"];
}

$prev_page = $page-1;
$next_page = $page+1;

$row_start = (($per_page*$page)-$per_page);
if($num_rows<=$per_page)
{
$num_pages =1;
}
else if(($num_rows % $per_page)==0)
{
$num_pages =($num_rows/$per_page) ;
}
else
{
$num_pages =($num_rows/$per_page)+1;
$num_pages = (int)$num_pages;
}
$row_end = $per_page * $page;
if($row_end > $num_rows)
{
$row_end = $num_rows;
}

$stmt = " SELECT Name,Studen_ID
FROM(
SELECT ROW_NUMBER() OVER(ORDER BY Name) AS RowID,Name,Studen_ID
FROM Studen WHERE Name LIKE '%".$strKeyword."%'
) AS tmp
WHERE tmp.RowID > $row_start AND tmp.RowID <= $row_end
";

$query = sqlsrv_query( $conn, $stmt );
if( $query === false ) {
if( ($errors = sqlsrv_errors() ) != null) {
foreach( $errors as $error ) {
echo "SQLSTATE: ".$error[ 'SQLSTATE']."<br />";
echo "code: ".$error[ 'code']."<br />";
echo "message: ".$error[ 'message']."<br />";
}
}
}

?>
<table width="600" border="1">
<tr>
<th width="50"> <div align="center">Student ID </div></th>
<th width="98"> <div align="center">Name Student </div></th>
<th width="98"> <div align="center">Class Name </div></th>

</tr>
<?php
while($result = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC))
{
?>
<tr>
<td><div align="center"><?php echo $result["Studen_ID"];?></div></td>
<td><?php echo $result["Name"];?></td>

</tr>
<?php
}
?>
</table>
<br>
Tổng số: <?php echo $num_rows;?> nhân viên : <?php echo $num_pages;?> trang :
<?php
if($prev_page)
{
echo " <a href='$_SERVER[SCRIPT_NAME]?Page=$prev_page&txtKeyword=$strKeyword'><< Trang trước</a> ";
}

for($i=1; $i<=$num_pages; $i++){
if($i != $page)
{
echo "[ <a href='$_SERVER[SCRIPT_NAME]?Page=$i&txtKeyword=$strKeyword'>$i</a> ]";
}
else
{
echo "<b> $i </b>";
}
}
if($page!=$num_pages)
{
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$next_page&txtKeyword=$strKeyword'>Trang kế tiếp>></a> ";
}
sqlsrv_close($conn);
?>
</body>
</html>

Date : 2019-08-24 17:03:04

By : rainkv

No. 3

Chaidhanan

โพสกระทู้ ( 9,586 )
บทความ ( 2 )

sorry
Code (PHP)

$stmt = " SELECT tmp.Name, tmp.Studen_ID, c.ClassName 
FROM(
  SELECT ROW_NUMBER() OVER(ORDER BY Name) AS RowID,Name,Studen_ID, Class_ID
  FROM Studen WHERE Name LIKE '%".$strKeyword."%'
) AS tmp
left join Class c on tmp.Class_ID = c.Class_ID
WHERE tmp.RowID > $row_start AND tmp.RowID <= $row_end
";

Date : 2019-08-25 07:14:40

By : Chaidhanan

No. 4

rainkv

โพสกระทู้ ( 0 )
บทความ ( 0 )

Thank you Thaicreate and Mr Chaidhanan community very much. I just learned about php so I don't have much experience. Looking forward to learning and sharing from the Thaicreate community and Mr Chaidhanan help.
Thank you!

Date : 2019-08-25 14:42:43

By : rainkv

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Re : I have paging problems with INNER JOIN table of sqlsrv with php.

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