php update เสร็จแล้วให้ delete จากตารางที่แสดงข้อมูลอยู่ครับ

<?php
         session_start();  
         include 'connect.php';

        $topup_id = $_GET['topup_id'];
        $member_id = $_GET['member_id'];
        $date_topup = $_GET['date_topup'];
        $time_topup = $_GET['time_topup'];
        $slip_topup = $_GET['slip_topup'];
        $bankname_topup = $_GET['bankname_topup'];
        $money_topup = $_GET['money_topup'];
        $type = 'เติมเงิน';
        $topup_status = 'สำเร็จ';

        $sql = "UPDATE topup SET topup_status = '$topup_status' WHERE topup_id = '$topup_id'";
        $result = mysqli_query($conn,$sql);
        
        $sql2 = "UPDATE member SET member_coin = (SELECT SUM(b.money_topup) FROM topup AS b WHERE b.member_id = member.member_id)";
        $result2 = mysqli_query($conn,$sql2)or die(mysql_error());

        $query3 = "INSERT INTO user_financial_history(member_id,topup_id,date_topup,time_topup,type,money_topup,slip_topup,status,bankname_topup) VALUES ('$member_id','$topup_id','$date_topup','$time_topup','$type','$money_topup','$slip_topup','$topup_status','$bankname_topup')";
        $result3 = mysqli_query($conn,$query3);

        $sql4 = "DELETE FROM topup WHERE topup_id='$topup_id'";
        $result4 = mysqli_query($conn,$sql4)or die(mysql_error());

        if($result && $result2 && $result3 && $result4){
                echo "<script type='text/javascript'>";
                echo "alert('เพิ่มเงิน $money_topup สำเร็จ');";
                echo "window.location ='admin_topup_check.php'; ";
                echo "</script>";
        }else{
                echo "error";
        }

  ?>