ขอวิธีบันทึกข้อมูล 2 ค่าจาก Dropdown list หน่อยค่ะ

                  <div class="modal-body">
                  <div class="form-group">
                  <label for="#" class="col-form-label">มอบให้</label><br>
                  <div class="form-group">
                  <select id= "ceo_name" name= "ceo_name" class="form-control">
                          <option class="hidden"  selected disabled>-- กรุณาเลือก --</option>
                          <?php
                          $strSQL = "SELECT * FROM user WHERE Identity = 'V'";			
                          $objQuery = mysql_query($strSQL);
			                    while($objResuut = mysql_fetch_array($objQuery))
			                    {?>
                          			<option value="<?php echo $objResuut["Name"];?>"><?php echo $objResuut["Name"]." - ".$objResuut["vip"];?></option>
			                    <?php
			                    }
			                    ?>
                  </select>
                  </div>
                  </div>
                  </div>

$ID = $_POST['ID'];
    $project_name = $_POST['project_name'];
    $project_detail = $_POST['project_detail'];
    $StartDate = $_POST['StartDate'];
    $EndDate = $_POST['EndDate'];
    $vip_mem = $_POST['vip_mem'];
    $name = $_POST['name'];
    $Department = $_POST['Department'];
    $Phone = $_POST['Phone'];
    $sumdate = $_POST['sumdate'];

$sql = "INSERT INTO  borrowreturn 
			
        (ID, 
        project_name, 
        project_detail, 
        StartDate, 
        EndDate, 
        vip_mem, 
        name, 
        Department, 
        Phone, 
        sumdate, 
        Record_date)
		
        VALUES ('$ID', 
        '$project_name', 
        '$project_detail', 
        '$StartDate',
        '$EndDate', 
        '$vip_mem',
        '$name',
        '$Department',
        '$Phone', 
        DATEDIFF('$EndDate' ,'$StartDate'), 
        NOW())";