ต้องการแสดงข้อมูลจาก mysql 3 column แบบ loop อัตโนมัติ

<?php $page = 'joblist';include 'include/menu.php'; ?>
<?php
 include "include/dbcon.php";
$link = mysqli_connect($host, $username, $password, $db);
$link -> set_charset("utf8");
/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$query = "SELECT * FROM jobs";

if ($result = mysqli_query($link, $query)) {
    $count=0;
    while ($row = mysqli_fetch_assoc($result)) {
        $position = $row['position'];
        $description = $row['description'];
echo "<div class='container'>
        <div class='row justify-content-start'>
        <div class='col-4'>
        

        <img class='image-responsive' width='100%' src='https://coda.newjobs.com/api/imagesproxy/ms/niche/images/articles/Liz/HumanResources2.jpg' / ><hr>
        <h2>{$position}</h2><hr>
        
        <p>{$description} </p>
        <a href='#'><button type='button' class='btn btn-info' style='width:100%'><<รายละเอียด>></button></a>
        </div>
        </div>
        </div>
        
        ";
        $count++;
         switch ($count){


        case  ($count % 4 == 0)     ;
        echo "<div class='clearfix visible-lg-block visible-md-block'></div>";        
        break       ; 

        case ($count % 2 == 0  && $count % 4 !==0 ) ;
        echo "<div class='clearfix visible-sm-block'></div>";
        break       ; 

                 }

}
mysqli_free_result($result);
}

/* close connection */
mysqli_close($link);
?>
</body>
</html>