ต้องการสร้าง Function Add Row ให้มีการใช้ Dropdown จากฐานข้อมุล เข้าไปแทรกในการ Add Rows

var admin;
	(function ($) {
		admin = {
			init: function () {
				$(".remove_position").live('click', function() {

					count = $('#count').val();
					count = count - 1;
					$('#count').val(count);

					$(this).closest('tr').remove();
				});

				$("#add_position").live("click", function() {
					if ($('#positions-table tbody tr:last').length > 0)
						var getNumber = parseInt($('#positions-table tbody tr:last').attr('id').replace('position-', ''), 10);
					else
						var getNumber = 0;
	
					var addNumber = getNumber + 1;

					$('#positions-table > tbody:first').append('<tr id="position-' + addNumber + '"><td><input type="text" name="name[]" value="" required /></td><td><input type="text" name="code[]" value="" size="4" required /></td><td align="center"><input type="button" name="remove_position" value="Remove" class="button remove_position" /></td></tr>');

										
					var rowCount = $('#positions-table tr').length;
					var rowCount = rowCount - 1;
					$('#count').val(rowCount);
				});
			}
		};

		$(document).ready(function() {
			admin.init();
		})
	})(jQuery);

<select>
<?php
$sql="select * from room_config where room_name";
	$query=mysql_query($sql);
	while($result=mysql_fetch_array($query)){?>
		<option value="<?php echo $result["room_code"]."#".$result["room_name"];?>" 
			<?php if($room_name==$result["room_name"]){
				  echo "selected";
			}?>>
			<?php echo $result["room_name"]." - ".$result["room_code"];?>
		</option>
?>
</select>